²log4+³log27-5^log 1+²log16

By Admin ReiPosted on December 2, 2022

²log4+³log27-5^log 1+²log16

$^{2} log(4) + ^{3} log(27) - ^{5} log(1) + ^{2} log(16) \ = : ^{2} log( {2}^{2} ) + ^{3} log {3}^{3} - ^{5} log( {5}^{0} ) + ^{2} log {2}^{4} \ = 2 + 3 - 0 + 4 \ = 9$