²Log2/3-²Log12 adalah

= (²log 2 – ²log 3) – (²log 4+ ²log 3)
= ²log 2 – ²log 3 – ²log 4 – ²log 3
= ²log 2 – 2 ²log 2 – 2. ²log 3
= 1 – 2 – 2 ²log 3
= – 2 ²log 3 – 1
atau
= -( 1 + 2 ²log 3)