∫(x3-x-1)(x2+1)dx =tolong beserta caranya kak

∫(x3-x-1)(x2+1)dx =tolong beserta caranya kak

integral
∫ axⁿ dx = (a xⁿ⁺¹)/(n+1)

Penjelasan dengan langkah-langkah:

∫(x³- x – 1)(x² + 1) dx =

= ∫ (x⁵ + x³ - x³ – x – x² – 1) dx

= ∫ (x⁵ – x²- x - 1) dx

$sf = frac{1}{5+1}x^{5+1} - frac{1}{2+1}x^{2+1} - frac{1}{1+1}x^{1+1} - frac{1}{0+1}x^{0+1} + c$

$sf = frac{1}{6}x^{6} - frac{1}{3}x^{3} - frac{1}{2}x^{2} - frac{1}1}x^{1} + c$

$sf = frac{1}{6}x^{6} - frac{1}{3}x^{3} - frac{1}{2}x^{2} - 1+ c$