0integral-1 (3x+2)⁵ dx =…

Jawaban:

₁³∫ √(3x + 2)⁵ dx =

u = 3x + 2 –> dx = 1/3 dx

x= 1 –> u = 5

x= 3 –> u = 11

.

₁³∫ √(3x + 2)⁵ dx = ₅¹¹∫ 1/3 . u⁵/² du

= 1/3 . 2/7 [ u ⁷/² ]¹¹₅

= 2/21 { 11⁷/² – 5⁷/² }

= 2/21 { 11³√11 – 5³√5}

= 2/21 { 1.331 √11 – 125 √5 }

Penjelasan dengan langkah-langkah:

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