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Quis spesial pangkat Kak @Roslinaros992 ^^

1.)
Diketahui :
A = 4
F = 6
I = 3

Tentukan :
A × F ÷ I + F – A
$2.) : 62 div 2 times 4 = ...$
$3.) : 3! + 4! = ...$
Centang biru : Tinggi sendiri ._.
Centang Merah : Terpisah ya 🙂 T_T

Tetap semangat ya para rekan semua :)

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Jawaban:

Diketahui :

A = 4

F = 6

I = 3

Tentukan :

A × F ÷ I + F – A

A × F ÷ I + F – A

= 4 × 6 ÷ 3 + 6 – 4

= (4 × 6)÷ 3) + 6 – 4

= (24 ÷ 3) + 6 – 4

= 8 + 6 – 4

= 14 – 4

= 10

No 2

62 ÷ 2 × 4

= (62 ÷ 2) × 4)

= 31 × 4

= 124

No 3

3! + 4!

= (3 × 2 × 1) + (4 × 3 × 2 × 1)

= (6 × 1) + (12 × 2 × 1)

= 6 + (24 × 1)

= 6 + 24

= 30

A × F : l + F – A = 4 × 6 : 3 + 6 – 4

= 24 : 3 + 6 – 4

= 8 + 6 – 4

= 14 – 4

= 10

62 : 2 × 4 = 31 × 4

= 120

3! + 4! = ( 3 × 2 × 1 ) + ( 4 × 3 × 2 × 1 )

= ( 6 × 1 ) + ( 12 × 2 × 1 )

= 6 + ( 24 × 1 )

= 6 + 24

= 30

SEMOGA MEMBANTU..

Gambar Jawaban