1. A.

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 frac{1}{8} +  frac{9}{4}   =
B.
 frac{3}{5} +  frac{1}{2} =
C.
 frac{1}{6} +  frac{1}{4} =
D.
 frac{2}{9} +  frac{1}{2} =
E.
 frac{2}{13} +  frac{5}{6} =
F.
 frac{4}{5} +2frac{1}{4} =
G.
 frac{5}{17} + 2 frac{2}{3} =
H.
 frac{5}{8} + 1 frac{1}{6} =
I.
3 frac{3}{10} + 2 frac{3}{8}
TOLONG SAMA CARA CARA NYA KELAS 5

1. A.

SOAL A.

 frac{1}{8} + frac{9}{4} = frac{(1 times 1) + (9 times 2)}{8} = frac{1 + 18}{8} = frac{19}{8} = 2 frac{3}{8}

SOAL B.

 frac{3}{5} + frac{1}{2} = frac{(3 times 2) + (1 times 5)}{10} = frac{6 + 5}{10} = frac{11}{10} = 1 frac{1}{10}

SOAL C.

 frac{1}{6} + frac{1}{4} = frac{(1 times 4) + (1 times 6)}{24} = frac{4 + 6}{24} = frac{10}{24} = frac{5}{12}

SOAL D.

 frac{2}{9} + frac{1}{2} = frac{(2 times 2) + (1 times 9 )}{18} = frac{4 + 9}{18} = frac{13}{18}

SOAL E.

 frac{2}{13} + frac{5}{6} = frac{(2 times 6) + (5 times 13)}{78} = frac{12 + 65}{78} = frac{77}{78}

SOAL F.

 frac{4}{5} + 2 frac{1}{4} = frac{4}{5} + frac{9}{4} = frac{(4 times 4) + (9 times 5)}{20} = frac{16 + 45}{20} = frac{61}{20} = 3 frac{1}{20}

SOAL G.

 frac{5}{17} + 2 frac{2}{3} = frac{5}{17} + frac{8}{3} = frac{(5 times 3) + (8 times 17)}{51} = frac{15 + 136}{51} = frac{151}{51} = 2 frac{49}{51}

SOAL H.

 frac{5}{8} + 1 frac{1}{6} = frac{5}{8} + frac{7}{6} = frac{(5 times 3) + (7 times 4)}{24} = frac{15 + 28}{24} = frac{43}{24} = 1 frac{19}{24}

SOAL I.

 3 frac{3}{10} + 2 frac{3}{8} = frac{33}{10} + frac{19}{8} = frac{(33 times 4) + (19 times 5)}{40} = frac{132 + 95}{40} = frac{227}{40} = 5 frac{27}{40}

Jawab:

A. frac{19}{8} = 2 frac{3}{8}

B. frac{11}{10} = 1 frac{1}{10}

C. frac{5}{12}

D. frac{13}{18}

E. frac{77}{78}

F. frac{77}{40} = 1 frac{37}{40}

G. frac{151}{51} = 2frac{49}{51}

H. frac{43}{24} = 1frac{19}{24}

I. frac{227}{40} = 5frac{27}{40}

Penjelasan dengan langkah-langkah:

A.

frac{1}{8} + frac{9}{4} \\ = frac{1}{8} + (frac{9}{4} atas bawah dikalikan 2 agar penyebut menjadi 8)

= frac{1}{8} + frac{18}{8} penyebut sudah sama tinggal ditambah yang atas

= frac{19}{8}

= 2 frac{3}{8}

B.

frac{3}{5} + frac{1}{2} \\= frac{3}{5} (dikali 2)+ frac{1}{2} (dikali 5)\\= frac{6}{10} + frac{5}{10}\\= frac{11}{10}\\= 1 frac{1}{10}

C.

frac{1}{6} + frac{1}{4} \\= frac{1}{6} (dikali 2) + frac{1}{4} (dikali 3)\\ = frac{2}{12} + frac{3}{12}\\ = frac{5}{12}

D.

frac{2}{9} + frac{1}{2} \\= frac{2}{9} (dikali 2) + frac{1}{2} (dikali 9)\\= frac{4}{18} + frac{9}{18}\\= frac{13}{18}

E.

frac{2}{13} + frac{5}{6} \\= frac{2}{13} (dikali 6) + frac{5}{6} (dikali 13)\\= frac{12}{78} + frac{65}{78}\\= frac{77}{78}

F.

frac{4}{5} + 2frac{1}{4}\\ = frac{4}{5} + 2frac{1}{4} disederhanakan 2 x penyebut (4) ditambah pembilang (1)

= frac{4}{5} + frac{9}{8}\\= frac{4}{5} (dikali 8) + frac{9}{8} (dikali 5)\\= frac{32}{40} + frac{45}{40}\\= frac{77}{40}\\= 1 frac{37}{40}

G.

frac{5}{17} + 2frac{2}{3}\\= frac{5}{17} (dikali 3) + frac{8}{3} (dikali 17)\\= frac{15}{51} + frac{136}{51}\\= frac{151}{51}\\= 2frac{49}{51}

H.

frac{5}{8} + 1frac{1}{6}\\= frac{5}{8} (dikali 3) + frac{7}{6} (dikali 4)\\= frac{15}{24} + frac{28}{24}\\= frac{43}{24}\\= 1frac{19}{24}

I.

3frac{3}{10} + 2frac{3}{8} \\= frac{33}{10} (dikali 4)+ frac{19}{8}(dikali 5)\\= frac{132}{40} + frac{95}{40}\\= frac{227}{40}\\= 5frac{27}{40}

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