1. Hitunglah pH dari larutan asam HCN 0,0001M, Ka = 10^-4​

Jawaban:

Gunakan rumus [H+] asam lemah :

[H+] = √Ka × M

[H+] = √10^-4× 10^-4

[H+] = 10^-4

pH = -log[H+]

pH = -log 10^-4

pH = 4

Penjelasan:

Jika kurang jelas silahkan bertanya