1. p³p⁴ x q³r²=

Posted on

2. X3y4 x (-y2)=
3. (-5xy³)²=
4. (a³b³)⁴=
5. ((-5xy³)²)²=

bonus poin, tpi harus jawab dlu…​

1. p³p⁴ x q³r²=

Penjelasan dengan langkah-langkah:

Nomor 1

p³p⁴ times q³r²= {p}^{3 + 4} {q}^{3} {r}^{2} = {p}^{7} {q}^{ 3} {r}^{2}

Nomor 2

x3y4 times ( - y2) \ = x times 3y times 4 times ( - 2y) \ = - x times 3y times 4 times 2y \ = - 24xy^{2}

Nomor 3

( - 5xy^{3} )^{2} = {( - 5)}^{2} times {x}^{2} times {( {y}^{3}})^{2} \ = {25x}^{2} times ( {y}^{3} )^{2} \ = {25x}^{2} {y}^{6}

Nomor 4

( {a}^{3} {b}^{3}{)}^{4} = ({ {a}^{3} })^{4} times ({ {b}^{3} })^{4} \ = {a}^{12} times (b ^{3} {)}^{4} \ = {a}^{12} {b}^{12}

Nomor 5

Salah soal kah? maaf blm bisa bantu