(1-x).(1+x).(1+x²).(1+x⁴).(1+x^8).(1+x³²)= ...mohon bantuannya dengan cara please:)

(1-x).(1+x).(1+x²).(1+x⁴).(1+x^8).(1+x³²)= …mohon bantuannya dengan cara please:)

Jawaban Terkonfirmasi

(1-x)(1+x)(1+x^2)(1+x^8)(1+x^32)
$= (1 - {x}^{2} )(1 + {x}^{2} )(1 + {x}^{4} )(1 + {x}^{8} ) \ (1 + {x}^{32} )$
$= (1 - {x}^{4} )(1 + {x}^{4} )(1 + {x}^{8} )(1 + {x}^{32} )$
$= (1 - {x}^{8} )(1 + {x}^{8})(1 + {x}^{32} )$
$= (1 - {x}^{16} )(1 + {x}^{32}) \ = 1 + {x}^{32} - {x}^{16} - {x}^{48}$

semoga membantu

trima kasi

Gambar Jawaban