1. [x-3] =2 2.[x+1]+[x+3]=6 3.[3x+5]=[x+7]persamaan nilai mutlak linear satu variabel
Jawab:
1. [x-3] = 2
X -3 = 2
X= 2+3
X = 5
2. [X+1]+[x+3] = 6
x+1 + x+3 = 6
2x+4 = 6
2x = 6-4
2x= 2
x = 2/2
x = 1
3. [3x+5] = [x+7]
3x -x = 7-5
2x = 2
X = 2/2
X = 1
Penjelasan dengan langkah-langkah: