1. [x-3] =2 2.[x+1]+[x+3]=6 3.[3x+5]=[x+7]persamaan nilai mutlak linear satu variabel​

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1. [x-3] =2 2.[x+1]+[x+3]=6 3.[3x+5]=[x+7]persamaan nilai mutlak linear satu variabel​

Jawab:

1. [x-3] = 2

X -3 = 2

X= 2+3

X = 5

2. [X+1]+[x+3] = 6

x+1 + x+3 = 6

2x+4 = 6

2x = 6-4

2x= 2

x = 2/2

x = 1

3. [3x+5] = [x+7]

3x -x = 7-5

2x = 2

X = 2/2

X = 1

Penjelasan dengan langkah-langkah: