100 ml larutan nh3 0,1 m di tambah 100 ml larutan (nh4)2so4 0,1 m berapa ph campuran tersebut (kb nh3 = 1,8 x 10^-5

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100 ml larutan nh3 0,1 m di tambah 100 ml larutan (nh4)2so4 0,1 m berapa ph campuran tersebut (kb nh3 = 1,8 x 10^-5

(OH-)= Kb x mol basa/mol garam = 1,8 x 10^-5 x 10/10 = 1,8 x 10^-5
pOH = -log (OH-) = -log 1,8 x 10^-5 = 5 – log 1,8
pH =14-pOH = 14-(5-log 1,8)= 9 + log 1,8