13.perhatikan gambar berikut

Jawaban:

A. 18 cm mendekati lensa

Penjelasan:

Diketahui :

– s1 = 12 cm

– s1' = 36 cm

– s2 = 12 + 6

= 18 cm

Ditanya :

–

Jawaban :

(:) Cari nilai f

1 / f = 1 / s1 + 1 / s1'

1 / f = 1 / 12 + 1 / 36

1 / f = ( 3 + 1 ) / 36

1 / f = 4 / 36

1 / f = 1 / 9

f = 9 cm

(:) Cari nilai s2'

1 / s2' = 1 / f – 1 / s2

1 / s2' = 1 / 9 – 1 / 18

1 / s2' = ( 2 – 1 ) / 18

1 / s2' = 1 / 18

s2' = 18 cm

Jadi, letak bayangannya bergeser :

A. 18 cm mendekati lensa