18. Bila f(x) = 2x³-6x, maka f(x + 1) adalah ​

Jawaban:

f(x) =2×3-6x

t(x+1) =2(x+1) ³-6(x+1)

f(x+1) =2(x³+3²+3x+1) -6x-6

f(x+1) =2×3+6x²+6x+2-6x-6

f(x+1) =2×3+6x²-4

Jawaban:

2x³ + 6x² – 4

Penjelasan dengan langkah-langkah:

f(x) = 2x³ – 6x

f(x + 1) = 2(x + 1)³ – 6(x + 1)

f(x + 1) = 2(x³ + 3x² + 3x + 1) – 6x – 6

f(x + 1) = 2x³ + 6x² + 6x + 2 – 6x – 6

f(x + 1) = 2x³ + 6x² – 4