18m pangkat 2 – 12 = 0
Jawab:
18m²–12=0
6(3m²–2)=0
m=–b±√b²–4ac/2a
a=3
b=0
c=–2
m=–0±√0²–4•3(–2)/2•3
m=0±2√6/6
m=0+2√6/6
m=0–2√6/6
m=√6/3
m=–√6/3
m=±√6/3
18m pangkat 2 – 12 = 0
Jawab:
18m²–12=0
6(3m²–2)=0
m=–b±√b²–4ac/2a
a=3
b=0
c=–2
m=–0±√0²–4•3(–2)/2•3
m=0±2√6/6
m=0+2√6/6
m=0–2√6/6
m=√6/3
m=–√6/3
m=±√6/3