194°f….Rtolong dibantu ya, terimakasih
~Suhu
__________
》Fahrenheit ke Reamur
194⁰F = 4/9 ( 194 – 32 )
= 4/9 ( 162 )
= 162 ÷ 9 × 4
= 18 × 4
= 72⁰R
194⁰F = 72⁰R
194°f….Rtolong dibantu ya, terimakasih
__________
》Fahrenheit ke Reamur
194⁰F = 4/9 ( 194 – 32 )
= 4/9 ( 162 )
= 162 ÷ 9 × 4
= 18 × 4
= 72⁰R
194⁰F = 72⁰R