2)Nilai a=10,maka nilai 4a=………
3)Jika Nilai p=5,maka nilai (2p_4)×(3p+5):60=………
1)Diketahui p=5.Nilai p+10=………
1. p+10 = 5 + 10 = 15
2. 4a = 4 x 10 = 40
1. p + 10 = 5+10= 15
2. 4a = 4×10 =40
3. (2p-4)×(3p+5):60
=(2×5 – 4) × (3×5 + 5) : 60
=6 × 20 : 20
=6