2 log 48 + 2 log akar 1/16-2log3

Logaritma.

²㏒ 48 + ²㏒ √(1/16) - ²㏒ 3
= ²㏒ 48 + ²㏒ 1/4 - ²㏒ 3
= ²㏒ (4 × 4 × 3) + ²㏒ 4⁻¹ – ²㏒ 3
= 2 ²㏒ 4 + 2㏒ 3 – 1 ²㏒4 - ²㏒ 3
= 2 (2) – 2
= 2

²log48+²log√1/16 – ²log 3
=²log 48+²log 2^-2 -² log 3
=²log(48/3) + (-2)
=²log 16 -2
=4-2
=2
jadikan jawaban terbaik jika membantu ya 🙂