2. Untuk grafik y = f(x) dengah x) = 8×2 – 16x + 6, tentukan: (skør 10)

Penjelasan dengan langkah-langkah:

f(x) = 8x² – 16x + 6

Titik potong sumbu x —–> y = 0

8x² – 16x + 8 = 0

( 4x – 2 ) ( 2x – 3 ) = 0

4x – 2 = 0

4x = 2

x = 2/4

x = 1/2 —-> ( 1/2 , 0 )

2x – 3 = 0

2x = 3

x = 3/2

x = 1 1/2 —-> ( 1 1/2 , 0 )

Titik potong sumbu y —-> x = 0

y = 8x² – 16x + 6

y = 0 – 0 + 6

y = 6 ——> ( 0 , 6 )

Sumbu simetris

a = 8

b = -16

xp = -b / 2a

xp = -(-16) / (2 × 8)

xp = 16 / 16

xp = 1

Nilai minimum

yp = 8x² – 16x + 6

yp = 8 (1)² – 16 (1) + 6

yp = 8 – 16 + 6

yp = -2

Koordinat titik puncak

( xp , yp ) —-> ( 1 , -2 )