20 gram Na OH ( Mr = 40) di larutkan di dalam 100 gram air = 100ml air tentukan:

a. Molaritas (M)
b. Melaritas (M)
c. Person serat (% B/B)

20 gram Na OH ( Mr = 40) di larutkan di dalam 100 gram air = 100ml air tentukan:

$mol : naoh \ = massa div mr \ = 20 div 40 \ = 0.5 : mol$

$liter= 100ml = 0.1 : l \ a. : molaritas \ = mol div liter \ = 0.5 div 0.1 \ = 5 : molar$

$b. : molalitas : kali : bukan : melaritas \ molalitas \ = frac{1000}{pelarut(gram)} times mol \ = frac{1000}{100} times 0.5 \ = 5 : molal$

$c. : persen( frac{b}{b} ) \ = frac{zat : terlarut}{zat : terlarut +pelarut } times 100% \ = frac{20gram}{20gram + 100gram} times 100% \ = frac{20}{120} times 100% \ = 16.66%( frac{b}{b} )$