21.Nilai maksimum untuk fungsi objektif​

Jawaban:

24

Penjelasan dengan langkah-langkah:

x + 2y = 16 → (0, 8) dan (16, 0)

3x + 2y = 20 → (0, 10) dan (20/3, 0)

x + 2y = 16

x = 16 – 2y

3x + 2y = 20

3 (16 – 2y) + 2y = 20

48 – 6y + 2y = 20

-4y = 20 – 48

y = -28/-4

y = 7

x = 16 – 2y

x = 16 – 2 . 7

x = 16 – 14

x = 2

(2, 7)

(0, 10), (0, 8) dan (2, 7)

f(x, y) = 5x + 2y

f(0, 10) = 5 . 0 + 2 . 10

f(0, 10) = 0 + 20

f(0, 10) = 20

f(0, 8) = 5 . 0 + 2 . 8

f(0, 8) = 0 + 16

f(0, 8) = 16

f(2, 7) = 5 . 2 + 2 . 7

f(2, 7) = 10 + 14

f(2, 7) = 24

jawabannya E. 24

Kode Kategorisasi : 12.2.2

Kelas 12

Pelajaran 2 – Matematika

Bab 2 – Program Linear

Kata kunci : Nilai maksimum