25. Dua buah benda masing-masing bermuatan listrik sebesar 6×10^-9C åada jarak 4 cm gata tolaK menolak antara kedua benda itu sebesar…… (k=9×10^9 Nm²/C²)

Diketahui
q₁ = q₂ = 6 x 10⁻⁹ C
r = 4 cm = 4 x 10⁻² m
k = 9 x 10⁹ Nm² / C²

ditanya
F = ………….. ?

jawab
F = k[q₁ . q₂]/r²
F = 9×10⁹ [ 6 x10 ⁻⁹]² / [4 x 10⁻²]²
F = 9×10⁹ [ 36 x 10⁻¹⁸ ]/ [ 16 x 10⁻⁴ ]
F = 9×10⁹ [ 9 x 10⁻¹⁸ ] /  [ 4 x 10⁻⁴ ]
F = 81 x 10⁻⁹ / 4 x 10⁻⁴
F = 20,25 x 10⁻⁵
F = 2,025 x 10 ⁻⁴N

Diketahui:
Q1 = 6.10^-9C
Q2 = 6.10^-9C
r = 4 cm => 0,04 = 4.10^-2 m
k = 9.10^9 Nm²/c²

tanya : F ?

jawab:
gunakan hukum coulumb

F = (k.Q1.Q2)/ r²
F = (9.10^9 . 6.10^-9. 6.10^-9) / (4.10^-2)²
F = (9.6.6 .10^9. 10^-9.10^-9) / 16.10^-4
F = (324 . 10^-9) / 16.10^-4
F = 324 / 16 . 10^-9 . 10^4
F = (20,25 x 10^-5) Newton

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