2log7+2log16-2log28=...

2log7+2log16-2log28=…

Jawaban Terkonfirmasi

Logaritma
Kelas X

²log 7 + ²log 16 – ²log 28
= ²log ⁷/₂₈ + ²log 16
= ²log ¼ + 4
= ²log 2⁻² + 4
= -2 + 4
= 2

Ingat :
1.) ᵃlog a – ᵃlog b = ᵃlog (a / b)
2.) ᵃlog aᵇ = b

Jawaban Terkonfirmasi

${}^{2} log(7) + {}^{2} log(16) - {}^{2} log(28) \ = {}^{2} log( frac{7 times 16}{28} ) \ = {}^{2} log( frac{16}{4} ) \ = {}^{2} log_{}(4) \ = {}^{2} log_{}(2 {}^{2} ) \ = 2. {}^{2} log(2) \ = 2 times 1 \ = 2$