2(t+3)=5(t-1)-7(t-3) - Universityku

2(t+3)=5(t-1)-7(t-3)

2t+6=5t-5-7t+21
2t-5t+7t=-5+21-6
4t=20
t=5

$2(t + 3) = 5(t - 1) - 7(t - 3) \ 2t + 6 = 5t - 5 - 7t + 21 \ 2t - 5t + 7t = - 5 + 21 - 6 \ 4t = 10 \ t = frac{10}{4} \ t = frac{5}{2} \ =2,5$