2× + 3y=14 × + 5y=21 Tentukan nilai eliminasi × dan subtitusi y

2x + 3y = 14 ¦ x1→ 2x + 3y = 14

x + 5y = 21 ¦x2 → 2x + 10 y = 42

2x + 3y = 14

2x + 10y = 42

———————- –

-7y = -28

y = -28 : -7

y = 4

x + 5y = 21

x + 5(4) = 21

x + 20 = 21

x = 21 – 20

x = 1

jadi nilai y = 27/7 dan nilai x = 12/7