3 log (2t-5)=2 log (2t-5)

By Admin ReiPosted on October 29, 2022

3 log (2t-5)=2 log (2t-5)

$t = 3$

PENJELASAN :

$log_{a} : f(x) = log_{b} : f(x) : : : dengan : : : a : neq : b$

$maka : : f(x) = 1$

Sehingga

$log_{3}(2t - 5) = log_{2}(2t - 5)$

$2t - 5 = 1$

$2t = 6$

$t = 3$