34. 11 cm 16 cm 23 cm Berapa cm²luas permukaan balok di atas?​

p = 11 cm

l = 16 cm

t = 23 cm

Luas permukaan balok = 2 x (pl + lt + pt)

L = 2 ( 11×16 + 16×23 + 11×23)

L = 2 ( 176 + 368 + 253 )

L = 2 x 797

L = 1594