3log12 + 3log4 – 2(3log4/3)…..?

3log12 + 3log4 – 2(3log4/3)

=3log12 + 3log4 – 3log(4/3)^2

= 3log (12×4/(16/9))

= 3log 48×(9/16)

= 3log( 3×9)

=3log 27

= 3log 3^3

=3. 3log 3

= 3×1 =3