3log48 – 5log125 – 3log16 + 5log25= Tolong jelaskan cara rumusnya:) terima kasih

Penjelasan dengan langkah-langkah:

3log48 – 5log125 – 3log16 + 5log25 =

(3log48 – 3log16) + ( 5log25 – 5log125) =

3log(48/16) + 5log(25/125) = 3log3 + 5log(1/5)

= 3log3 + 5log(5^(-1))

= 1 + (-1) x 5log5

= 1 + (-1) = 0