3^Log81+3^log81-3^Log27

3^Log81+3^log81-3^Log27

³log81 + ³log81 – ³log27

= ³log3⁴ + ³log3⁴ – ³log3³

= (4 + 4 – 3) x ³log3

= (8-3) x 1

= 5

$log_{3}(81) + log_{3}(81) - log_{3}(27)\= log_{3}(81 times 81 div 27)\= log_{3}(243) = 5$