3x+5y=15 dan x+2y=6 tentukan substitusi campuran dan eliminasi

3x+5y=15
x+2y=6 | x3
——————
3x+5y=15
3x+6y=18
————– –
-y = -3
y = 3

x+2y=6
x+2(3)=6
x=6-6
x=0

3x + 5y = 15 |×2|
x + 2y = 6 |×5|
↓

6x + 10y = 30
5x + 10y = 30
y hangus dan sistem operasi (-)
6x – 5x = 1x
30 – 30 = 0
1x = 0
x = 0/1
x = 0

Substitusi :
3x + 5y = 15
3(0) + 5y = 15
0 + 5y = 15
y = 15/5
y = 3.

HP = { x , y }
{ 0 , 3 }

Pembuktian :
x + 2y = 6
0 + 2(3) = 6
6 = 6
🙂