4. Diketahui persegi panjang PQRS dengan panjang PQ = (5x + 3)cm dan QR = (2x + 1) cm. Jika keliling persegi panjang PQRS tidak kurang dari 38 cm, berapa nilai x yang mungkin?

PQ = 5X + 3 = 38
= 5X = 38 – 3
= 5X = 35
= X = 35/5
= X = 7
QR = 2X + 1 = 38
= 2X = 38 – 1
= 2x = 37
= x = 37/2
= 18,5
PQ = 5(7) + 3
= 35 + 3
= 38
QR = 2(18,5) + 1
= 37 + 1
= 38
Jadi , Nilai x (PQ) = 7 dan Nilai x (QR) = 18,5

SEMOGA BERMANFAAT