|4x+12| ≤16 tolong yah​

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|4x+12| ≤16 tolong yah​

|4x + 12| ≤ 16

4|x + 3| ≤ 16

|x + 3| ≤ 4

-4 ≤ x + 3 ≤ 4

-4 – 3 ≤ x ≤ 4 – 3

-7 ≤ x ≤ 1

Jawaban:

|4x+12| ≤16

-16≤4x+12≤16

-16-12≤4x+12-12≤16-12

-28≤4x≤4

-28/4≤4x/4≤4/4

-7≤x≤1

Penjelasan dengan langkah-langkah:

bentuk umum pertidaksamaan linear

  • |p|≤q, -q≤p≤q