5,6,7 sama caranya ya jangan ngasal

No 5)
berarti :
(2x-x²) = B(x+1)
B(x+1) = 2x – x²
y = x + 1 –> x = y -1
B(y) = 2(y-1) – (y-1)²
B(y) = 2y -2 – (y²-2y+1)
B(y) = -y² + 4y -3
B(x) = -x² +4x -3
jadi :
B(x-1) = -(x-1)² + 4(x-1) -3
B(x-1) = – (x²-2x+1) +4x -4-3
B(x-1) = -x² +2x -1 + 4x -7
B(x-1) = -x² + 6x -8

no 6)
a = 3x + 1 –> 3x = a – 1 –> x = (a-1)/3
h(a) = 9(a-1)/3)² + 6(a-1)/3 + 6
h(a) = 9(a²-2a+1)/9 + 2a – 2 + 6
h(a) = (a²-2a+1) + 2a + 4
h(a) = a² + 5
h(a+2) = ((a+2)² + 5 = a² +4a + 9
h(2a) = (2a)² + 5 = 4a² + 5.
jadi :
h(a) + h(a+2) – h(2a) =
(a² + 5) + (a² +4a + 9) – (4a² +5) =
-2a² + 4a + 9

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