6 : ( y+2 ) = 9 : ( 2y-1 )

6 : ( y+2 ) = 9 : ( 2y-1 )

Aljabar

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$frac{6}{(y + 2)} = frac{9}{(2y - 1)} \ \ 9(y + 2) = 6(2y - 1) \ \ 9y + 18 = 12y - 6 \ \ 9y - 12y = - 6 - 18 \ \$

$- 3y = - 24 \ \ y = 8$

→ 6 : (y + 2) = 9 : (2y – 1)

→ $tt frac{6}{y+2} = frac{9}{2y - 1}$

→ 9(y + 2) = 6(2y – 1)

→ 9y + 18 = 12y – 6

→ 9y – 12y = -6 – 18

→ -3y = -24

→ y = 8

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