f(x)=x³ + x! + x² × ⅜
f'(5)=….?
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Diketahui:
f(x)=x³ + x! + x² × ⅜
Ditanya:
f'(5)=….?
Dijawab:
f(x)=x³ + x! + x² × ⅜
f(x)=x³ + x! + x² × ⅜f'(5)=….?
- f(5) = x³ + x! + x² × ⅜
- f(5) = 5³ + 5! + 5² × ⅜
- f(5)= ( 5 × 5 × 5 ) + ( 5 × 4 × 3 × 2¹ ) + ( 5 × 5 ) × ⅜
- f(5) = ( 25 × 5 ) + ( 20 × 6¹) + ( 25 ) × ⅜
- f(5) = ( 125 + 120 + ) ( 25 × ⅜ )
- f(5) = ( 245 + ( 25 × ⅜ )
- f(5) = ( 245 +( 25 × ⅜)
- f(5) = ( 245 ( 25 × ⅜ )
- f(5) = 245 + 9.375
- f(5) = 254.375
[ Kesimpulan ]
- Hasil dari f(5) = 254.375
Semoga Bisa Bermanfaat-!