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$tt : {3}^{1} + {3}^{3} - 5 = ....$

$tt : = (3) + (3 times 3 times 3) - 5$

$= tt : 3 + (9 times 3) - 5$

$= tt : 3 + 27 - 5$

$= tt : 30 - 5$

$= { boxed{ tt{25}}}$

= 3¹ + 3³ – 5

= 3 + (3 x 3 x 3) – 5

= 3 + (9 x 3) – 5

= 3 + 27 – 5

= 30 – 5

= 25