(9×4+kx²-3x+5) dibagi dengan (3x-2) sisanya 23, maka nilai k​

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(9×4+kx²-3x+5) dibagi dengan (3x-2) sisanya 23, maka nilai k​

3x – 2 = 0

3x = 2

x = 2/3

Teorema Sisa

P(x) = S(x)

P(2/3) = S(2/3)

9x⁴ + kx² – 3x + 5 = 23

9(2/3)⁴ + k(2/3)² – 3(2/3) + 5 = 23

9(16/81) + 4k/9 – 2 + 5 = 23

16/9 + 4k/9 + 3 = 23

(16 + 4k)/9 = 20

16 + 4k = 180

4k = 180 – 16

4k = 164

k = 164/4

k = 41