Tolong dibantu ya ini tentang integral

A. ∫ (x³+2x)/x dx = ∫ x² +2 dx = 1/3 x³ + 2x + c
b. ∫ (3x-2) x/ x dx = ∫ 3x – 2 dx = 3/2 x² – 2x + c
c. ∫ (4x+2)(3x²+1)/(2x)  dx= ∫(12x³ + 6x² + 4x + 2) /(2x) d
= ∫ 6x² + 3x + 2 + 1/x dx = 2x³ + 3/2 x² + 2x + ln x + c
d.∫ 3x(2x² +1)² dx = ∫3x(4x⁴+ 4x²+1) dx = ∫ 12x⁵+12x³+ 3x dx
= 2x⁶ + 3x⁴+ 3/2 x² + c
 

A. ∫ (x³ + 2x)/x dx = ∫ (x³/x + 2x/x) dx
= ∫ (x² + 2) dx
= 1/3 x³ + 2x + C

b. ∫ (3x – 2)x/x dx = ∫ (3x – 2) dx
= 3/2 x² – 2x + C

c. ∫ [(4x + 2)(3x² + 1)] / (2x) dx
= 1/2 ∫ [(4x + 2)(3x² + 1)] / x dx
= 1/2 ∫ (12x³ + 4x + 6x² + 2)/x dx
= 1/2 ∫ (12x³ + 6x² + 4x + 2)/x dx
= 1/2 ∫ (12x² + 6x + 4 + 2/x) dx
= 1/2 (4x³ + 3x² + 4x + 2㏑ IxI) + C
= 2x³ + 3/2 x² + 2x + ㏑ IxI + C

d. ∫ 3x(2x² + 1)² dx = 3 ∫ x(2x² + 1)²
= 3 ∫ x(4x⁴ + 4x² + 1) dx
= 3 ∫ (4x⁵ + 4x³ + x) dx
= 3 (2/3 x⁶ + x⁴ + 1/2 x²) + C
= 2x⁶ + 3x⁴ + 3/2 x² + C