Please tolong dibantu ya..

A) ∫ 4x(2x – 1/x) dx =∫8x² – 4 dx = 8/3 x³ – 4x + c

b) ∫ x⁻¹ (3x- x²) dx = ∫ 3 – x dx = 3x – 1/2 x²  +c

c) ∫(√x – 1/x)² = ∫ x  – 2.1/x. √x + 1/x² dx
=∫ x – 2(x)^(-1) (x)^(1/2)+ x^(-2) dx
= ∫ x – 2 x^(-1/2) + x^(-2)
= 1/2 x² – 4 √x – 1/x + c

d) ∫x^(1/2) (10x +2) dx = ∫10 x^(3/2) + 2x^(1/2)
= 4x^(5/2) + 4/3 x^(3/2) + c
= 4x² √x + 4/3 x√x + c