Tolong jawab yaa, soal mtk no 9

Tinggi segitiga dec
t² = sm²-a²
t² = 13² – 5²
t = √169-25
t = √144
t = 12 cm

luas segitiga dec
= 1/2 . 10 . 12
= 60 cm²

luas prsegi pnjg
= 13 . 10
= 130 cm²

luas segitiga ae & bc
= 1/2 . 6 . 13
= 3 . 13
= 39 cm²

jadi luas segitiga abcde
→ → 60 + 130 + 39
= 229 cm² [c]

(dijaminbenar )