Dik: persamaan garis lurus PX + QY= 1 melalui titik(3,-2)dan (-5,4) tentukan nilai P dan Q

PX  + QY = 1
P(3) + Q(-2) = 1
3P – 2Q = 1
6P – 4Q = 2
-4Q = 2 – 6P
4Q = 6P – 2

P(-5) + Q(4) = 1
-5P + 4Q = 1
-5P + 6P – 2 = 1
P – 2 = 1
P = 1 + 2
P = 3

3P – 2Q = 1
3(3) – 2Q = 1
9 – 2Q = 1
-2Q = 1 – 9
-2Q = -8
Q = -8/-2
Q = 4

jadi, nilai P = 3 dan Q = 4