dua dadu ditos, tentukan peluang: a. dadu berjumlah 8/10, b. dadu berjumlah 9, c. mata dadu pertama 4 dan yang kedua 5

N(s) = 36

a. n(a) = (2,6)(3,5)(4,4)(5,3)(6,2) = 5
p(a) = n(a)/n(s) = 5/36
n(b) = (4,6)(5,5)(6,4) = 3
n(b) = n(b)/n(s) = 3/36
p(avb) = 5/36 + 3/36 = 8/36 = 2/9

b. n(a) = (3,6)(4,5)(5,4)(6,3) = 4
p (a) = n(a)/n(s) = 4/36 = 1/9

c. n(a) = (4,5) = 1
p(a) = n(a)/n(s) = 1/36