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Jawaban:

jawaban a

$int(10x sqrt{x} - frac{1}{ sqrt{x} } + 5)dx \ = int(10 {x}^{ frac{3}{2} } - {x}^{ - frac{1}{2} } + 5)dx \ = frac{10}{1 + frac{3}{2} } {x}^{1 + frac{3}{2} } - ( frac{1}{ 1 - frac{1}{2} } ) {x}^{ 1 - frac{1}{2} } + 5x + c \ = frac{10}{ frac{5}{2} } {x}^{ frac{5}{2} } - frac{1}{ frac{1}{2} } {x}^{ frac{1}{2} } + 5x + c \ = 4 {x}^{2} sqrt{x} - 2 sqrt{x} + 5x + c$

Penyelesaian:

∫ (10x√x – 1/√x + 5) dx

∫ (10x^3/2 – x^-1/2 + 5) dx

= 10/(5/2) x^5/2 – 1/(1/2) x^1/2 + 5x + C

= 4x^5/2 – 2x^1/2 + 5x + C

= 4x^2√x – 2√x + 5x + C

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Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Integral Tak Tentu

Kode: 11.2.10

Kata Kunci: integral