Perhatikan gambar! panjang dc adalah…… tolong jawab ya..

Pertama cari EB menggunakan phytagoras (segitiga siku”)
EB^2 = EA^2 – AB^2
EB^2 = 13^2 – 5^2
EB^2 = 169 – 25
EB^2 = 144
EB = akar pangkat 2 dari 144
= 12 cm

DB = 1/2 EB
= 1/2 x 12
= 6 cm

Cari DC menggunakan phytagoras.
DC^2 = CB^2 – BD^2
DC^2 = 10^2 – 6^2
DC^2 = 100 – 36
DC^2 = 64
DC = akar pangkat 2 dari 64
= 8 cm (C)

Semoga membantu:)

Cari BE=> BE = √(13^2-5^2)
= √(169-25)
= √144
= 12
BD = 1/2BE = 1/2×12 = 6
dari pithagoras
BC^2 = BD^2 + DC^2
DC^2 = BC^2 – BD^2
DC^2 = 10^2 – 6^2
DC^2 = 100 – 36
DC^2 = 64
DC = √64
DC = 8