#kedudukan dua garis lurus sistem linear
1. 2x-3y+2=0 ; 4x-6y=0
Yg jago mtk mampir dong, 1 soal aja biar paham sayanya. 🙂
1. x=0
2(0)-3y+2=0
-3y=-2
y=2/3 (0,2/3)
y=o
2x-3(0)+2=0
2x=-2
x= -1 (-1,0)
2. 4x-6y=o
x=0
4(0) -6y =0
y= -6 (0,-6)
y=0
4x-6(0)=0
x= 4 (4,0 )