3 log 24 dikurang 3 log 2 akar 3 + 2.3 log 1/9 + 3 log 2 1/4

³log 24 – ³log 2√3 + 2 ³log ¹/₉ + ³log 2 ¹/₄

=³log 24 – ³log 2√3 + ³log (¹/₉)² + ³log ⁹/₄

=³log 24(¹/₉)²(⁹/₄)/2√3

=³log ⁴⁸/₃₆ √3

=³log ⁴/₃√3

=³log 4 + ³log √3 – ³log 3

= ³log 4 + ¹/₂³log 3  - 1

=³log 2² + ¹/₂ – 1

= 2 ³log 2 – ¹/₂