f(x) = 9x – 6x + 100
f(3) + f(4) = ???
Nt : Sepi .__
Izi Bet Anak Esde Pun Bisa ._
~Fungsi~
f(3) = 9x – 6x + 100
f(3) = 9(3) – 6(3) + 100
f(3) = 27 – 18 + 100
f(3) = 9 + 100
f(3) = 109
==================
f(4) = 9x – 6x + 100
f(4) = 9(4) – 6(4) + 100
f(4) = 36 – 24 + 100
f(4) = 12 + 100
f(4) = 112
===================
= f(3) + f(4)
= 109 + 112
=
Kesimpulan
= f(x) = 9x – 6x + 100
= f(3) + f(4)
= 221
Jawaban:
f(x) = 9x – 6x + 100
f(3) + f(4) =
f(3) = 9(3) – 6(3) + 100
f(3) = (9 × 3) – (6 × 3) + 100
f(3) = 27 – 18 + 100
f(3) = 9 + 100
f(3) = 109
f(4) = 9(4) – 6(4) + 100
f(4) = (9 × 4) – (6 × 4) + 100
f(4) = 36 – 24 + 100
f(4) = 12 + 100
f(4) = 112
f(3) + f(4) = 109 + 112 = 221