Nilai 2pq =3 -akar2, maka nilai 8p^2q^2 adalah...

Nilai 2pq =3 -akar2, maka nilai 8p^2q^2 adalah…

2pq = 3 – √2 (bagi 2 kedua ruas)
$p.q = frac{(3 - sqrt{2}) }{2}$

Pakai Sifat Perpangkatan (Eksponen)
x²y² = (xy)²
(a – b)² = a² – 2ab + b²

$8 {p}^{2} {q}^{2} = 8( {p.q)}^{2} \ = 8 ({ frac{3 - sqrt{2} }{2} })^{2} \ = frac{8}{ {2}^{2} } (3 - sqrt{2} )^{2} \ = frac{8}{4} ( {3}^{2} - 6 sqrt{2} + 2) \ = 2(9 + 2 - 6 sqrt{2} ) \ = 22 - 12 sqrt{2}$

Semoga Membantu 🙂