Bntu jawab nomer 2 yg B kak

Bntu jawab nomer 2 yg B kak

Penjelasan dengan langkah-langkah:

$(f circ g)(x) = {x}^{2} + 3x + 1$

$g(x) = x + 1$

$:$

Misal.

$x + 1 = a$

$a + 1 = x$

$a = x - 1$

$:$

Maka.

$f(x) = {x}^{2} + 3x + 1$

$f(x) = {(x - 1)}^{2} + 3.(x - 1) + 1$

$f(x) = {x}^{2} - 2x + 1 + 3x - 3 + 1$

$f(x) = {x}^{2} + x - 1$

$f(2) = {2}^{2} + 2 - 1$

$f(2) = 4 + 1$

$f(2) = 5$