Mohon bantuannya kakak, kerjakan nomor 5 sampai 8 dengan caranya. Mohon sekali ya kakak bantuannya

6)
2^2x – 10.2^x+1 + 64 = 0
a² – 20a + 64 = 0
(a – 16)(a – 4) = 0
a – 16 = 0
2^x = 16 = 2⁴
x = 4

a – 4 = 0
2^x = 4 = 2²
x = 2

jawaban : D

5) 4/5 (2^(3x-2)) + 8^x / 20 = 1

(16 (2^(3x-2)) + 8^x ) / 20 = 1

(2^4 . 2^(3x-2) + (2^3)^x) / 20 = 1

(2^ (4+3x-2) + 2^(3x)) / 20 = 1

(2^ (2+3x) + 2^(3x)) / 20 = 1

(2^2 . 2^(3x) + 2^(3x)) / 20 = 1

(2^(3x) . (2^(2) + 1)) / 20 = 1

2^(3x) / 4 = 1

2^(3x) = 2^2
3x = 2
x = 2/3 (D)

7) 2x / 2^(3x+6) = 2^6 . 2^(3x/2) . 2^3(3x/2)
2^x . 2^(-3x-6) = 2^(6+3/2x+9/2x)
x-3x-6 = 6+3/2x + 9/2x
-4x-12 = 12 + 3x+ 9x
-24 = 16x
x = – 3/2 (B)

8) 3√((3^3)2x-1) = 3^((-5/3)3x)
3^1. 3^((6x-3)/2) = 3^(-5x)
2/2 + (6x-3)/2 = -5x
(2+6x-3)/2 = -5x
6x-1 = -10x
16x = 1
x = 1/16 (D)